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Alternative Energy – CrossFire Fusor
Author: Moacir L. Ferreira Jr.
The CrossFire Fusor is a nuclear fusion reactor designed by Moacir L. Ferreira Jr. for fusing atomic nucleus in order to produce enormous quantities of energy without pollution and no neutron hazards.
This fusion reactor is comprised by six superconducting magnets disposed to form a magnetic cusp region in where positive ions are injected. At the magnetic cusp region is applied a negative voltage and at the opposite end of each magnet is applied a positive voltage. The ions are accelerated electrostatically towards the negative potential passing through the magnetic cusp reaching the chamber interior, where the ions are confined radially by magnetic fields and longitudinally by electric fields, that is a three-dimensional confinement. The ion injection is done continuously surrounding the magnetic cusp region to perform a three-dimensional injection. The positive voltage confines only reactants allowing the products from the fusion reactions to escape.
The ions are injected with great kinetic energy (600KeV), but in small quantities, and calculations are done for the magnetic and electric fields to confine the ionized plasma, keeping it away from the chamber walls.
The CrossFire Fusor was based on stellated polyhedrons, accelerating electrostatically reactants inwardly to the central edges and products escaping at peripheral vertices after overcoming the confinement of electric fields.
Although this reactor uses electrostatic acceleration like the Farnsworth–Hirsch Fusor, it doesn’t have a central-grid to cause losses. Then the ions, under electrostatic acceleration, can reach great kinetic energy with inexpressive energy consumption. Also, there is no recirculation of electrons to induce excessive electromagnetic radiation.
Due to use of electrostatic acceleration, the CrossFire Fusor is able to fuse not only conventional fuels such as deuterium-tritium, but also aneutronic fuels like boron hydrides, helium-3 and lithium hydrides. Aneutronic fusion reactions release millions of times more energy than the fossil fuels, almost not emit neutrons and the products of the reaction is mainly helium-4 that is safe and clean.
The fusion reaction products are positively charged which can be deflected by magnetic and electric fields. Then a conversion to electricity is relatively simple. The conversion is done during the neutralization by a positive electric voltage to slow down and an electron gun to neutralize. The current of electrons and the electric voltage is equal to electric power (P=V×I).
CrossFire Fusor provides solutions for two drawbacks that are common to nuclear fusion:
1. Ionic saturation, excess of ions in the chamber, which could be solved by a stronger superconducting magnet, by decreasing the specific ionization of the plasma and by having an adequate escape mechanism.
2. Electromagnetic radiation losses, that could be reduced by a reflective internal coating in order to reflect the electromagnetic radiation back to the plasma.
The advantages of the CrossFire Fusor over others fusion approaches are:
1. Three-dimensional injection and confinement, which increase the probability and velocity of the fusion reactions.
2. Escape mechanism, which reduces the ionic saturation and instabilities of energy, and provides both with efficiency, propulsion and electricity generation.
3. A method for electricity conversion that can exceed 95% of efficiency.
4. Simple and consistent calculations, which give a reasonable degree of predictability.
As an alternative source of energy, this fusion reactor could replace the 10 billion tons/year of carbon dioxide from fossil fuels to only 7600 tons/year of clean, inert, safe and light helium gas, which can reduce drastically the Global Warming Problem.
Official website
Article Source: http://www.articlesbase.com/technology-articles/alternative-energy-crossfire-fusor-850827.html
About the Author
Degree in Computational Science by Federal University of Paraná (2003) and Electronic Technician by Federal Center of Technological Education of Paraná (1991)
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What is the energy density of the ELECTRIC field for a wire that is 10mm in diameter and carrying 10A?
Is it zero? I think this is trick question. Does a current carrying wire induce an electric field as well as a magnetic field. I calculated the energy density of the magnetic field but the next question asked for the energy density of the electric field.
The question should read the energy density at the SURFACE of the wire.
The largest constant magnetic field achieved in the laboratory is about 40 T.?
(a) What is the magnetic energy density due to this field?
(b) What magnitude electric field would have an equal energy density?
Answer these correctly first, and get best answer!
How do you find the magnetic field of a circularly polarized plane wave given the electric field?
ok, for one of the prioblems I’m given the equations of an electric field:
Ex(z,t) = E0sin(kz-wt)
Ey(z,t) = E0cos(kz-wt)
for a circularly polarized plane wave of light traveling in the z direction.
I have to show the magnetic field, energy density, and Poynting vector for this wave.
the energy density is u = .5 [eE2 + B2/u]
the Poynting vector is S = (E x B)/u
but I don’t know how to find B…? any advice?
Uniform electric and magnetic fields E and B occupy the same region of free space.?
If the amplitude of the electric field is 630 V/m , what is the amplitude of the magnetic field B if the energy densities in the electric and magnetic fields are equal?
Use c = 3.00×10^8 m/s for the speed of light in a vacuum.
Energy Density of Magnetic and Electric Fields?
On a clear day at a certain location, a 91 V / m vertical electric field exists near the Earth’s surface. At the same place, the Earth’s magnetic field has a magnitude of 4.30 10-5 T. Compute the energy densities of the two fields. ie the magnetic field and the elctric field.
There is obviously some formula ( but i cannot seem to find it in my book) for these as it looks like a relatively simple substitution question, how can you calculated energy densities when you are only given one piece of information for each field type.
Thanks so much!
4.3 x 10^-5T
I’m assuming that the current is not changing with time other than the initial turn-on transient.
When the current has reached a steady state (didn’t say reached zero, but some final state), you are in the area of electromagnetics called electro/magnetostatics and the magnetic and electric fields are uncoupled. For the situation that you describe (I’m assuming no stationary charges external to the wire), the Electric Field Density is zero.
You might be tempted to use Gauss’ Law to find the Electric Field from an individual electron as it moved down the wire, but the summation at any particular point in space from all charges moving in the wire will sum to zero.
When the current is first turned on you will have a changing magnetic field and therefore an electric field. However, that electric field will die away rapidly.
part A
B^2 / (2*mu)
now find an E field thats equivalent
the B vector is at right angles to the E vector given by the S vector