Magnetic Field Generator

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How Does the Magnetic Energy Generator Work

Most alternative energy sources such as solar panels are rather large in size and require a whole lot of specialized equipment in order to function the way they should. If you compare just the size of a solar panel with that of a magnetic energy generator, it may seem difficult to believe that the considerably smaller sized magnetic energy generator would be capable of creating enough energy to fully or even partly power any home.

In fact, looking at most magnetic generators, you may be skeptical about them being able to create any energy whatsoever. They may look fairly simple; most simply utilize magnets positioned on a gear or disc around a central axle. This rotates using the principle of perpetual motion and power is generated. But how does it keep rotating and where does the power come from? This looks too simple to even be credible!

Magnets Both Repel And Attract

The interesting thing about magnets that is also the key to the generating ability of a magnetic generator is that they have specific polarities at each end. Remember playing with magnets as a child? You were able to pull them toward each other if the opposite polarities were facing each other and then push them away again by simply flipping one magnet over and getting the same polarities to face each other.

It is this use of polarity that is the secret to how the generator works. When magnets are arranged with a specific polarity arranged in a certain way and a second magnet is introduced, it can keep a gear continually in motion. This is because as the axle rotates, the polarities are alternately aligned and reversed. The repulsion/attraction of the magnets creates a field and a third magnet or another mechanism is used in order to convert that field into electricity.

The Amount Of Power Depends On The Size Of The Generator

The amount of power you can generate depends largely on the size of the generator and the strength and number of magnets you are using. If the magnets you use are very strong and there are quite a few of them, the field can also be quite strong and the amount of energy generated will also be quite large.

However, even if you are not interested in completely powering your home with a magnetic generator, it is still quite easy for you to reduce your energy bills and that can be a huge relief to many people. An average family can spend in the neighborhood of 0 each month for their daily energy needs. If you can even halve the amount of power you are drawing from the commercial power grid, you will be able to save a substantial amount of money.

Making the decision to move to alternative power sources should not have to be a big decision. The beauty of a magnetic generator is that they are inexpensive and simple to build and do not require the same space commitment that other energy sources may require.

If you are interested in building a generator, you can find some good information and plans online. In addition to telling you what materials you need, these plans also demonstrate in detail how to assemble the generator so that you can begin to reduce your power needs today.

About the author: To learn more about how to construct your own magnetic energy generator and see magnetic generator plans, visit Magnetic Energy Source.

Source: http://www.isnare.com/?aid=507516&ca=Home+Management

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10 Responses to Magnetic Field Generator

  1. Abdul basit Narejo says:

    question about electric generator how do we calculate magnetic field intensity?
    an alternating generator operating 50hz has a coil of 200 turns while coil has an area of 120 cm*cm. calculate the magnetic field intensity applied to rotate the coil to produce the maximum voltage of 240volts?

  2. Chris F says:

    magnetic field in generator?
    One generator uses a magnetic field of 0.177 T and has a coil area per turn of 0.0466 m2. A second generator has a coil area per turn of 0.0181 m2. The generator coils have the same number of turns and rotate at the same angular speed. What magnetic field should be used in the second generator, so that its peak emf is the same as that of the first generator?

  3. JullyWum says:

    Max. emf E output given by ..
    E = BANω
    B = ANω / E

    A = 120.0^-4 m² .. (taking 120cm*cm to mean cm²)
    ω = 50*2π 100π rad/s

    B = (120.0^-4 m²)(200)(100π rad/s) / 240 .. .. ►B = 3.14 T

  4. Sturm Vogel says:

    Peak emf in a generator is given by the formula Ɛ = N*A*B*ω. Since number of turns and angular speed are equivalent, they can be pulled out of the equation, leaving just Ɛ = A*B.

    For the first generator, the peak emf is:
    Ɛ = 0.177 T x 0.0466 m² = 8.25 x 10^-3 V

    To solve for the magnetic field in the second generator, arrange for the product of the area and the magnetic field to be equal to the peak emf of the first generator.
    8.25 x 10^-3 V = 0.0181 m² x B

    Now solve for B.
    B = 8.25 x 10^-3 V / 0.0181 m² = 0.456 T

  5. RaviP says:

    Physics–electric generator magnetic field emf?
    An electric generator consists of turns of wire formed into a rectangular loop a = 0.05 m by b = 0.03 m placed entirely in a uniform magnetic field with magnitude Bo=2.5-T. What is the maximum value of the emf produced when the loop is spun at w=1000 rev/min about an axis perpendicular to B?

    Answer is suppose to be 196 but i dont understand how to get it.
    yes 500 turns

  6. rozeta53 says:

    How many turns of wire? I think they have to be n=500, haven’t they?

    Emax=nabB₀ω
    where ω=2πw/60 rad/s

    Edit:
    ω=2π*1000/60=100π/3
    Emax=500*0.05*0.03*2.5*100π/3
    Emax=196.35 V

  7. Xuion says:

    Magnetic field, coil generator?
    Hey guys, I’v got this question in an exam coming up and have no idea how to answer it to be honest!

    If a coil of wire is rotated in a magnetic field to form a generator and has the ends of the coil connected to a voltmeter using two slip ring, what sort of voltage is produced? Sketch the shape of the voltage with time, for one revolution of the coil if it turns at 2 revolutions per second
    Hey guys, I’v got this question in an exam coming up and have no idea how to answer it to be honest!

    If a coil of wire is rotated in a magnetic field to form a generator and has the ends of the coil connected to a voltmeter using two slip ring, what sort of voltage is produced? Sketch the shape of the voltage with time, for one revolution of the coil if it turns at 2 revolutions per second

    EDIT
    To mmac63, Ok, so your saying that the more cycles, the higher the sinewave goes because you have a lower and higher peak? I find all of this hard to put in words but I think I understand.. Thankyou so much

  8. Matt says:

    Basic AC Generator, question on magnetic field?
    Ok i am building a basic ac generator for class (IE a wire loop spinning in a magnetic field) and need to know what factors to look at in magnets (Strength, distance apart etc) and whats more important to consider.

    Please help and if possible include sources

  9. mmac63 says:

    the answer depends on the magnetic field stength, A/C power as in normal power is 50cycles. So ya got 2htz (cycles) so draw a line with a equal wave above and below it,and make/keep it close to the axis line as ya will have jackshit of sinewave !! suspect it to be in millivolts.

  10. mensajeroscuro says:

    Well, i would suggest you put the wire loop in the static part of the generator and make the magnet turn. You can use a static magnet to get a little ac current. I would advice you use the strongest magnet you can get so you need less wire turns. Now it all will depend on if you want a big current or a big voltage. With big voltage you need more turns and with more current but less voltage use less turns.

    Hope this helps.

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